If x = -0.5, then which of the following has the smallest value? Option 1) Option 2) Option 3)  Option 4) 1Option 5)

$x= 0.5$

$As\: \frac{1}{x^{2}} \: and\, 2^{x}= will \: be +ve$

$\frac{1}{x}= -\frac{1}{0.5}= -2$

$2^{1/x}=2=\frac{1}{4}=.15$

$\frac{1}{.5^{1/2}}=+ve, so \frac{1}{x}\: is\: least$

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