If x = -0.5, then which of the following has the smallest value?

  • Option 1)

    2^{1/x}

  • Option 2)

    \frac{1}{x}

  • Option 3)

    \frac{1}{x^{2}}

     

  • Option 4)

    1

  • Option 5)

    2^{x}

Answers (1)

          x= 0.5

As\: \frac{1}{x^{2}} \: and\, 2^{x}= will \: be +ve

\frac{1}{x}= -\frac{1}{0.5}= -2

2^{1/x}=2=\frac{1}{4}=.15

\frac{1}{.5^{1/2}}=+ve, so \frac{1}{x}\: is\: least
 

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