# The average of marks obtained by 120 candidates was 35. If the average of the passed candidates was 39 and that of the failed candidates was 15, then the number of those candidates, who passed the examination, was Option 1) 100Option 2) 110Option 3) 130Option 4) 150Option 5) 120

$Avg. \: Of\: marks = 35$
$sum \: of \: marks = 35*120 = 4200$
$let \: the\: no. \: of \: passed\: candidates = x$
$no. \, of\: failed = y$
$x+y= 120 --------(i)$
$39x+15y=4200 -----(ii)$
$multiply\: (i) by \: 15 \: and \: then \: solving (i) & (ii)$
$-24x = -2400$
$x = 100$

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