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The population of a town is 12000, if the number of males be increased by 6% and that of females by 8%, the population would be increased to 12800. Find the strength of females in the town.

 

  • Option 1)

     

    3500   

     

  • Option 2)

     

    4000

     

  • Option 3)

     

    4500

     

  • Option 4)

     

    4200

     

  • Option 5)

     

    5000

     

Answers (3)

best_answer

Let's assume Males = x

Number of female = 12000 - x

As per the question,

x*(1.06) + (12000 - x)*(1.08) = 12800

x = 10,000

Females = 15000 - 10,000 => 5,000

Posted by

rishi.raj

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Let's assume Males = x

then females = 12000-x

now, 12000 + 6%f + 8%m = 12800

so, 6%f + 8%m = 800

6/100x + (8 ( 12000 - x)) /100 = 800 

6x -8x + 96000 = 800 * 100

x  = 8000

if males are 8000 then females are 12000-8000 = 4000.

 

 

 

 

 

 

 

Posted by

Vineet sharma

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Males Increased - 6% 

Female Increased - 8% = 6% + 2% 

The population of a town is 12000

12000× 6%= 12000× 6÷100 = 720

Then, 128000 - 12000 = 800

Then, 800 - 720 = 80

Extra females,

2% = 80 

1% = 40

100% = 4000

Females = 4000 (Answer)

Males = 12000-4000 = 8000

Posted by

Suman naskar

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