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The product of 10 consecutive even numbers is always divisible by

Option 1)
$2^{10}$
Option 2)
$3(2)^{9}$
Option 3)
$2^{10}\times10!$
Option 4)
$4^{10}$
Option 5)
$None\: of\: these$

Answers (1)

best_answer

The product of 10 even number must be multiple of 10 multiple of 2

Hence divisible by 2¹⁰

Posted by

rishi.raj

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