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There are 3 containers A, B and C which contain water, milk and acid respectively in equal quantities. 10% of the content of A is taken out and poured into B. Then, the same amount from B is transferred to C, from which again the same amount is transferred to A. What is the proportion of milk in container A at the end of the process?

  • Option 1)

    1/20

  • Option 2)

    1/11

  • Option 3)

    1/21

  • Option 4)

    2/13

  • Option 5)

    9/10

Answers (1)

best_answer

3 containers = A, B, C

Equal quantities = M:W:A

10 % = 1/10 taken out

Total transfer = 2

Total final mix = 1/(11)2

= 1/ 121

So container of A = 121-100 = 21

1/21

Posted by

rishi.raj

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