There are 3 containers A, B and C which contain water, milk and acid respectively in equal quantities. 10% of the content of A is taken out and poured into B. Then, the same amount from B is transferred to C, from which again the same amount is transferred to A. What is the proportion of milk in container A at the end of the process?
3 containers = A, B, C
Equal quantities = M:W:A
10 % = 1/10 taken out
Total transfer = 2
Total final mix = 1/(11)2
= 1/ 121
So container of A = 121-100 = 21
1/21