There are two containers: the first contains 500ml of alcohol, while the second contains 500 ml of water. Three cups of alcohol from the first container is removed and is mixed well in the second container. Then three cups of this mixture is removed and is mixed in the first container. Let ‘A’ denote the proportion of water in the first container and ‘B’ denote the proportion of alcohol in the second container. Then A,

  • Option 1)

    A > B

  • Option 2)

    A \rightarrow B

  • Option 3)

    A = B

  • Option 4)

    Cannot be determined

  • Option 5)

    A < B

Answers (1)

Let the capacity of each = 100 ml

So 300 ml removed and poured into second

First vessel = 200 ml alcohol

Second = 500 ml water+ 300 ml A

Ratio = 5:3

Proportion of alcohol = 3/8

If 300 ml removed from second  = 300 x 5/8 = 187.5 ml water

= 112.5 ml alcohol

Now poured so vessel = 200 + 112.5 = 312.5 A

= 187.5 ml

Hence ratio = 5:3 proportion of water = 3/8

So A= B

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