What is the last remainder when 223 is successively divided by 4, 5 and 6?

 

  • Option 1)

     

    5

     

  • Option 2)

     

    0

     

  • Option 3)

     

    6

     

  • Option 4)

     

    1

     

  • Option 5)

     

    3

     

Answers (1)

The last remainder when 223 is successively divided by 4, 5 and 6 is:

             \begin{matrix} 4 & 223 & \\ 5 & 55&3 \\ 6&11 &0 \\ & 1& 5 \end{matrix}

Remainder= 5

 

             

 

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