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24. Figure shows a cyclic process. When a given mass of a gas is expanded from state A to state B, it absorbs 30J of heat energy. When the gas is adiabatically compressed from state B to state A, the work done on the gas is 50 J. The change in internal energy of the e gas in the process A → B is

Option: 1

80 J


Option: 2

20 J


Option: 3

-20 J


Option: 4

-50 J


Answers (1)

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In the process B → A, work is done on the gas. Hence\mathrm{(\Delta W)_{B \rightarrow A}=-50 \mathrm{~J}} Since this process is adiabatic,\mathrm{(\Delta Q)_{B \rightarrow A}=0}. From the first law of thermodynamics, the change in internal energy in this process is

\mathrm{\begin{aligned} & (\Delta U)_{B \rightarrow A}=(\Delta Q)_{B \rightarrow A}-(\Delta W)_{B \rightarrow A} \\ & =0-(-50)=+50 \mathrm{~J} \end{aligned}}

Since the process is cyclic, there is no net change in internal energy. Hence

\mathrm{(\Delta U)_{A \rightarrow B}=-(\Delta U)_{B \rightarrow A}=-50 \mathrm{~J}}

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Deependra Verma

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