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25.3 g of sodium carbonate (Na2CO3) is dissolved in enough water to make 250 ml of solution. If sodium carbonate dissociates completely, the molar concentration of sodium ion (Na+) and carbonate ion \left ( \text{CO}_{3}^{2-} \right )  are respectively (Molar mass of Na2CO3 = 106 g mol-1

Option: 1

0.477 M and 0.477 M


Option: 2

0.955 M and 1.910 M


Option: 3

1.910 M and 0.955 M


Option: 4

1.90 M and 1.910 M


Answers (1)

best_answer

\mathrm{\text { Number of moles of } Na _{2} CO _{3}=\frac{25.3}{106}=0.239 \text { moles }}

\mathrm{\text { Molarity of solution }=\frac{0.239}{0.25}=0.956\text { mol/litre }}

\mathrm{Na _{2} CO _{3} \longrightarrow 2 Na ^{+}+ CO _{3}^{2-}}

\mathrm{\therefore \text { Concentration of } CO _{3}^{2-}=0.956 M}

\mathrm{\text { Concentration of } Na ^{+}=2 \times 0.956=1.912 M}

Therefore, the correct option is (3).

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Nehul

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