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  • 2.967 g is produced when 5 g of <img alt="\mathrm{Ag}" src="https://entrancecorner.oncodecogs.com/g

2.967 g \mathrm{Ag} is produced when 5 g of \mathrm{Ag} salt of an organic dibasic acid is heated. What is the molecular formula of the salt if weight percentage of C is 8 times that of \mathrm{H} and 1/2 times that of \mathrm{O}.\mathrm{\left(M_{\mathrm{AgNO_{3}}}=108\right)}

Option: 1

\mathrm{C}_3 \mathrm{H}_4 \mathrm{O}_6


Option: 2

\mathrm{C}_4 \mathrm{H}_3 \mathrm{O}_3


Option: 3

\mathrm{C}_4 \mathrm{H}_6 \mathrm{O}_6


Option: 4

\mathrm{C}_4 \mathrm{H}_6 \mathrm{O}_3


Answers (1)

best_answer

\mathrm{RH}_2 \longrightarrow \mathrm{RAg}_2 \longrightarrow \mathrm{Ag}

on applying the principle of atom conservation to \mathrm{Ag}.

\mathrm{\frac{5}{M_{\left(\mathrm{RAg}_2\right)}} \times 2=\frac{2.967}{108} \times 1}

\mathrm{M_{\left(RAg_{\left._2\right)}\right.}=\frac{5 \times 2 \times 108}{2.967}=364 \mathrm{~g} / \mathrm{mol}}

\mathrm{\begin{aligned} \\\text{M}_{\text{RH}_{2}}=364-216+2\\ \end{aligned}}

               =150 \mathrm{~g} / \mathrm{mol}

Element Percent % Ratio Least Ratio Simplest Ratio
C 8 8/12=067 1.0 2
H 1 1/1=1 1.5 3
O 16 16/16=1 1.5 3

Empirical Formula =\mathrm{C}_2 \mathrm{H}_3 \mathrm{O}_3

Empirical Formula Mass = 75

\mathrm{n=\frac{150}{75}=2}

Molecular Formula =\left(\mathrm{C}_2 \mathrm{H}_3 \mathrm{O}_3\right)_2

                               =\mathrm{C}_4 \mathrm{H}_6 \mathrm{O}_6

Posted by

Sayak

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