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A 4:1 molar mixture of He and CH4 is contained in a vessel at 20 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the ratio of moles of He : CH4 in the mixture effusing out initially?

Option: 1

1 : 8


Option: 2

8 : 1


Option: 3

1 : 5


Option: 4

7 : 1


Answers (1)

best_answer

We have
Molar ratio of He and CH4 is 4:1
Again, the total pressure is given = 20bar
Thus, the partial pressure ratio of He and CH4 = 16 : 4

\\\mathrm{\frac{n_{He}}{n_{CH_{4}}}\: =\: \sqrt{\frac{M_{CH_{4}}}{M_{He}}}\: x\: \frac{P_{He}}{P_{CH_{4}}}}\\\\\mathrm{\sqrt{\frac{16}{4}}\: x\: \frac{16}{4}\: =\: 8:1}

Therefore, Option(2) is correct

Posted by

HARSH KANKARIA

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