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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)

Option: 1

30 J


Option: 2

40 J


Option: 3

10 J


Option: 4

20 J


Answers (1)

best_answer

 Loss in Energy = \frac{1}{2}mv^{2}-mgh

= \frac{1}{2} \times 1\times 400-1\times 18\times 10

= 200-180 = 20J

Posted by

shivangi.shekhar

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