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A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is:

Option: 1

Zero


Option: 2

MV


Option: 3

1.5 MV


Option: 4

2 MV


Answers (1)

best_answer

As we learnt in 

Impulse -

vec{I}=int_{t_{1}}^{t_{2}}vec{F}cdot dt

 Impulse = Change in momentum

I=mv-(-mv)=2mv

Posted by

shivangi.bhatnagar

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