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  • A conducting rod of length l=2m is moving with velocity  in a  constant magnetic field of s

A conducting rod of length l=2m is moving with velocity 5ms^{-1} in a  constant magnetic field of strength 0.5T. The power generated in rod is 20W. Find the resistance R of rod.

Option: 1

1.25\Omega


Option: 2

3.04\Omega


Option: 3

2.60\Omega


Option: 4

2.1\Omega


Answers (1)

best_answer

As we learnt

 

Electric Power -

 

P=I^{2}R=\left ( \frac{Blv}{R} \right )^{2}\cdot R

P= \frac{B^{2}l^{2}v^{2}}{R}

-

 

 

 

P= \frac{B^{2}l^{2}v^{2}}{R}

R= \frac{B^{2}l^{2}v^{2}}{P}

R= \frac{(0.5)^{2}*(2)^{2}*(5)^{2}}{20}

R=1.25\Omega

Posted by

Riya

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