Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A conducting rod of length l=2m is moving with velocity  in a  constant magnetic field of s

A conducting rod of length l=2m is moving with velocity 5ms^{-1} in a  constant magnetic field of strength 0.5T. The power generated in rod is 20W. Find the resistance R of rod.

Option: 1

1.25\Omega


Option: 2

3.04\Omega


Option: 3

2.60\Omega


Option: 4

2.1\Omega


Answers (1)

best_answer

As we learnt

 

Electric Power -

 

P=I^{2}R=\left ( \frac{Blv}{R} \right )^{2}\cdot R

P= \frac{B^{2}l^{2}v^{2}}{R}

-

 

 

 

P= \frac{B^{2}l^{2}v^{2}}{R}

R= \frac{B^{2}l^{2}v^{2}}{P}

R= \frac{(0.5)^{2}*(2)^{2}*(5)^{2}}{20}

R=1.25\Omega

Posted by

Riya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

No NEET UG 2025 re-test for MP candidates as high court stays single judge order
anam-khan

'NEET 2025 in dark': MP High Court orders re-test for Indore, Ujjain students; MCC counselling delayed
anam-khan

Punjab’s new 2-year MBBS bond, fee hike ‘exploitation’, ‘unfair’; interns, doctors shut OPDs in protest

Latest Question