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A container holds 5 moles of an ideal gas at a temperature of 300 \mathrm{~K}. The gas exerts a pressure of 2 \mathrm{~atm} on the container walls. Calculate the volume of the container.

Option: 1

61.57 L


Option: 2

62.57 L


Option: 3

61.75 L


Option: 4

61L


Answers (1)

best_answer

We'll use the ideal gas law to solve this problem. The ideal gas law is given by:

Where: - P is the pressure (in atm), V is the volume (in liters),  n is the number of moles of the gas R is the ideal gas constant (R=0.0821 \mathrm{~L} \ atm / K \ mol) , T is the temperature (in Kelvin)

Given: n=5 moles P=2 \mathrm{~atm}; \ T=300 \mathrm{~K}

We want to solve for V.

1. Rearrange the ideal gas law to solve for V :

V=\frac{n R T}{P}

2. Plug in the given values:

V=\frac{(5 \text { moles }) \times(0.0821 \mathrm{~L} \mathrm{~atm} / \mathrm{K} \mathrm{mol}) \times(300 \mathrm{~K})}{2 \mathrm{~atm}}

3. Calculate the volume (V):

V=\frac{(5 \times 0.0821 \times 300)}{2} \mathrm{~L}

4. Calculate the final volume: 

V \approx 61.575 \mathrm{~L}

So, the volume of the container is approximately 61.575 liters.

Posted by

Irshad Anwar

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