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A 5.0 L elast contains \mathrm{32\, g} at oxygen at \mathrm{27^{\circ}C}
[Assume \mathrm{O_{2}} is betwaing ideally]
The pressure involev the elask in bar is-
[Given \mathrm{R=.0831 \mathrm{~L}_{\text {bar }} \mathrm{K}^{-1} \mathrm{~mol}^{-1}}]

 

 

Option: 1

5.986


Option: 2

4.986


Option: 3

3.896


Option: 4

4.896


Answers (1)

best_answer

Exam the ideal gas equation,
\mathrm{P=\frac{n R T}{V} \quad P =\text { pressure of oxygen } }
                         \mathrm{V =\text { volume of oxygen } }
                         \mathrm{T =\text { Temperature of oxygen in } k }
                          \mathrm{n =\text { Number of Moles of oxygen } }

\mathrm{n=\frac{32}{32}=1 }
\mathrm{p=\frac{1 \times 0831 \times 300}{5} }

\mathrm{p=4.986 \, \mathrm{bar} }
 

Posted by

Ritika Kankaria

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