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A film of water is formed between two straight parallel wires, each 10 \mathrm{~cm} long and at a separation of 0.5 \mathrm{~cm}. The work that must be done to increase the separation between the wires by 1 \mathrm{~mm} is (surface tension of water \mathrm{=7.0 \times 10^{-2} \mathrm{Nm}^{-1}} )

Option: 1

\mathrm{7.0 \times 10^{-5} \mathrm{~N}}


Option: 2

\mathrm{1.4 \times 10^{-5} \mathrm{~N}}


Option: 3

\mathrm{7.0 \times 10^{-7} \mathrm{~N}}


Option: 4

\mathrm{1.4 \times 10^{-7} \mathrm{~N}}


Answers (1)

best_answer

\mathrm{F=2 \sigma l. Work \, \, done \, \, is \, \, W=F S=2 \sigma l S=2 \times 7.0}\mathrm{ \times 10^{-2} \times 0.1 \times 0.001=1.4 \times 10^{-7} \mathrm{~N}, which \, \, is\, \, choice (d).}

Posted by

himanshu.meshram

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