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  • A full wave rectifier circuit with diodes $\left(D_1\right)$ and $\left(D_2\right)$ is shown in the figure. If input supply voltage $\mathrm{V}_{\mathrm{in}}=220 \sin (100 \pi t)$ volt, then at $t=15 \mathrm{msec}$

Q.20) A full wave rectifier circuit with diodes $\left(D_1\right)$ and $\left(D_2\right)$ is shown in the figure. If input supply voltage $\mathrm{V}_{\mathrm{in}}=220 \sin (100 \pi t)$ volt, then at
$t=15 \mathrm{msec}$

 

A) $D_1$ and $D_2$ both gre reverse biased
 

B) $D_1$ is forward biased, $D_2$ is reverse biased
 

C) $D_1$ is reverse biased, $D_2$ is forward biased
 

D) $D_1$ and $D_2$ both are forward biased 

Answers (1)

best_answer

 \begin{aligned}
&\text { At } t=15 \mathrm{~ms}=0.015 \mathrm{~s}:\\
&V_{\mathrm{in}}=220 \sin (100 \pi \cdot 0.015)=220 \sin (1.5 \pi)=220 \cdot(-1)=-220 \mathrm{~V}
\end{aligned}

So the input voltage is negative at this moment.
In a center-tap full-wave rectifier:
- During positive half-cycle, $D_1$ conducts and $D_2$ is reverse biased.
- During negative half-cycle, $D_2$ conducts and $D_1$ is reverse biased.

Since the input is negative at $t=15 \mathrm{~ms}$, this is the negative half-cycle.
So:
- $D_1$ is reverse biased
- $D_2$ is forward biased

Answer: (3) $D_1$ is reverse biased, $D_2$ is forward biased.

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Dimpy

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