Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A gramophone record is revolving with an angular velocity . A coin is placed at a distance r from the centre of the

A gramophone record is revolving with an angular velocity \omega. A coin is placed at a distance r from the centre of the record. The static coefficient of friction is \mu. The coin will revolve with the record if

Option: 1

\text{r}\geq\frac{\mu{\text{g}}}{\omega^{2}}


Option: 2

\text{r}=\mu{\text{g}}{\omega^{2}}


Option: 3

\text{r}<\frac{\omega^{2}}{\mu\text{g}}


Option: 4

    \text{r}\leq\frac{\mu\text{g}}{\omega^{2}}


Answers (1)

best_answer

\\ \text{When the disc spins the frictional force between the gramophone} \\ \text{record and coin is} \ \mu$ mg \\ The coin will revolve with record, if\\ $\mathrm{F}_{\text {frictional }} \geq \mathrm{F}$ centripetal $\mu \\ \\ \mathrm{mg} \geq \mathrm{m} \omega^{2} \mathrm{r}$ \\ \\ $\frac{\mu g}{r} \geq w^{2}$

r \leq \frac{\mu g}{\omega^2}

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET MBBS cut-off for OBC category in top 20 government medical colleges
anam-khan

MP HC allows NTA to declare NEET UG 2025 results except for 11 centres in Indore
anam-khan

NEET UG 2025: HC grants stay on result after Chennai students point to power cut in exam centre

Latest Question