Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixtu

A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture ?

Option: 1

5.25 bar, 19.75 bar


Option: 2

4.75 bar, 23.45 bar


Option: 3

6.20 bar, 20.44 bar


Option: 4

5.50 bar, 21.75 bar


Answers (1)

best_answer

Number of moles of O_2 = 70.6g / 32g = 2.21 moles
And number of moles of Ne_2 = 167.5 g / 20g = 8.375 moles
Now, mole fraction of O_2 = 2.21 / (2.21+8.375)
= 0.21
And mole fraction of Ne_2 = 8.375 / (2.21+8.375)
= 0.79
Now, according to Dalton’s law of partial pressure, we have:
Partial pressure = Mole fraction x Total pressure
Thus, partial pressure of O_2 = 0.21 x 25 bar
= 5.25 bar
And, partial pressure of Ne_2 = 0.79 x 25 bar
= 19.75 bar
Option (a) is correct

Posted by

Deependra Verma

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2025 city intimation slip by April 26; download at neet.nta.nic.in
anam-khan

CM MK Stalin challenges union home minister Amit Shah on NEET, delimitation
anam-khan

Kota: NEET aspirant dies of heart attack; police recover prescriptions, medicines from room

Latest Question