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  • A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is then:

Option: 1

S2 = 3S1


Option: 2

S2 = 4S1


Option: 3

S2 = S1


Option: 4

S2 = 2S1


Answers (1)

best_answer

 u = 0    t1 = 10 sec    t2 = 20 sec

s = ut +\frac{1}{2}at^{2}

s_{1} = \frac{1}{2}a{t_{1}}^{2}

s_{2} = \frac{1}{2}a{t_{2}}^{2}

\therefore \frac{s_{1}}{s_{2}} =\left ( \frac{t_{1}}{t_{2}} \right )^{2} = \left ( \frac{10}{20} \right )^{2} = \frac{1}{4}

\Rightarrow s_{2} = 4s_{1}

 

Posted by

Ritika Kankaria

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