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A point source of sounds of natural frequency 256 Hz and receiver R are moving along line with speed u = 10 m/s, towards a reflecting surface which is approaching them speed u as shown in figure .

 

If speed of sound in air is 300 m/s, then wavelength and frequency of reflected wave received by R are respectively-
 

Option: 1

\frac{330}{289} \, m and 289 Hz


Option: 2

\frac{340}{289} \, m and 289 Hz


Option: 3

\frac{330}{272} \, m and 289 Hz.


Option: 4

\frac{340}{272} \, m and 289 Hz.


Answers (1)

best_answer

Assuming the reflecting surface to be at rest.

\begin{aligned} & f^{\prime}=256\left(\frac{330+20}{330-20}\right) \mathrm{Hz}=289 \mathrm{~Hz} . \\ & \lambda^{\prime}=\frac{V^{\prime}}{f^{\prime}}=\frac{330+10}{280}=\frac{340}{289} \mathrm{~m} \end{aligned}

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HARSH KANKARIA

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