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  • A ray is incident at an angle of incidence i on one surface of a small angle prism (with the angle of prism A) and emerges normally from the opposite surface. If the refractive i

A ray is incident at an angle of incidence i on one surface of a small angle prism (with the angle of prism A) and emerges normally from the opposite surface. If the refractive index of the material of the prism is \mu then the angle of incidence is nearly equal to:

Option: 1

\frac{A}{2\mu}


Option: 2

\frac{2A}{\mu}


Option: 3

{\mu A}


Option: 4

\frac{\mu A}{2}


Answers (1)

best_answer

The angle of incidence =i

The angle of the prism =A

The angle of emergence =e

the refractive index of the material of the prism is \mu

For a small angle prism, angle of deviation,  \delta=(\mu-1) \mathrm{A}

but we have \delta =i+e-A

Using e=0

we get \delta =i-A

on comparing we get

\begin{array}{l} (\mathrm{i}-\mathrm{A})=(\mu-1) \mathrm{A} \\ \Rightarrow \mathrm{i}=\mu \mathrm{A} \end{array}

 

Posted by

Sanket Gandhi

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