Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A small loop of wire of area A =  and resistance R = <img alt="10\Omega" src="https://learn.careers360.co

A small loop of wire of area A = 2 m^2 and resistance R = 10\Omega is initially kept in a uniform magnetic field  B of intensity 10^{-3}T  in such a way that the field is normal to plane of the loop . 

When it is pulled out of magnetic field , the charge q that flows through coil is 

Option: 1

2 \times 10 ^{-4}C


Option: 2

2 \times 10 ^{-5}C


Option: 3

4 \times 10 ^{-4}C


Option: 4

4 \times 10 ^{-5}C


Answers (1)

best_answer

As we have learned

Induced Charge -

dq= i.dt= \frac{-N}{R}\frac{d\phi }{dt}.dt

dq= \frac{-N}{R}d\phi

 

- wherein

Induced Charge time independent

 

 Charge in flux whem loop is pulled out of magnetic field 

d \phi = BA

Acc. faradays law 

\varepsilon = \frac{-d\phi }{dt}

Current induced in loop is 

i= \varepsilon/R = \frac{-1}{R}\frac{d\phi }{dt}

Charge flown 

q=idt

q=\frac{-1}{R}d\phi

q=\frac{1}{10}\times 10^{-3}\times 2= 2 \times 10^{-4}C

 

 

 

 

Posted by

Deependra Verma

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Punjab’s new 2-year MBBS bond, fee hike ‘exploitation’, ‘unfair’; interns, doctors shut OPDs in protest
anam-khan

NEET UG 2025 counselling likely to begin on July 1; AIQ seat allocation, court hearing updates
anam-khan

NEET UG: Delhi HC seeks NTA's response on plea alleging defective biometric system at centre

Latest Question