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  •   A student measures the time period of 100 oscillations of a simple pendulum four times.  The data set is 90 s, 91 s, 95 s and 92 s.  If the minimum

  A student measures the time period of 100 oscillations of a simple pendulum four times.

 The data set is 90 s, 91 s, 95 s and 92 s.  If the minimum division in the measuring clock is 1 s,

  then the reported mean time should be :

Option: 1

 92 \pm 2 sec


Option: 2

92 \pm 5 sec


Option: 3

92 \pm 1.8 sec


Option: 4

92 \pm 3sec


Answers (1)

best_answer

As we learnt in

Time period of oscillation of simple pendulum -

T=2\pi \sqrt{\frac{l}{g}}

- wherein

l = length of pendulum 

g = acceleration due to gravity.

 

Sum of all observation = 90 + 91 + 95 + 92 = 368

Average =\frac{368}{4}=92

Sum of modulus observations = 2 + 1 + 3 = 6

\therefore   Average error =\frac{6}{4}=1.5,  rounded of 2.

\therefore  Final answer =92\pm 2

Posted by

seema garhwal

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