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  • A tennis ball (treated as hollow spherical shell) starting from O rolls down a hill. At point A the ball becomes air borne leaving at an angle of <img alt="30^{\circ}" src="https://learn.caree

A tennis ball (treated as hollow spherical shell) starting from O rolls down a hill. At point A the ball becomes air borne leaving at an angle of 30^{\circ} with the horizontal. The ball strikes the ground at B . what is the value of the distance AB ?

(Moment of interia of a spherical shell of mass m and radius R about its diameter = \frac{2}{3}mR^{2})

Option: 1

1.87m


Option: 2

2.08m


Option: 3

1.57m


Option: 4

1.77m


Answers (1)

best_answer

Velocity of the tennis ball on the surface of the earth or ground

v=\sqrt{\frac{2 g h}{1+\frac{k^{2}}{R^{2}}}}

(where k = radius of gyration of spherical shell = \sqrt{\frac{2}{3}} R )

 

Horizontal range AB =   \frac{v^{2} \sin 2 \theta}{g}


=\frac{(\sqrt{\frac{2 g h}{1+k^{2} / R^{2}}})^{2} \sin \left(2 \times 30^{\circ}\right)}{g}

 

= 2.08 m

Posted by

Ritika Jonwal

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