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  • A wheel rotates with constant acceleration of 2.0\; rad/s^2, if the wheel starts from rest the number of revolutions it makes in the first t

ten sec

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Given, \alpha = 2 \: rad/s^{2}

\Theta = \omega _{0}t +\frac{1}{2}\alpha t^{2}

As the initial angular velocity is zero. Hence we can calculate \Theta the angle rotated in first 10 seconds by, \Theta = \frac{1}{2}2^{2}\times 10 = 20 \: rad

Number of revolutions, \frac{\Theta }{2\pi} = \frac{20}{2\times 3.14} = 3.18

Posted by

Abhishek Sahu

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