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# A wheel rotates with constant acceleration of 2.0\; rad/s^2, if the wheel starts from rest the number of revolutions it makes in the first t

ten sec

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Given, $\alpha = 2 \: rad/s^{2}$

$\Theta = \omega _{0}t +\frac{1}{2}\alpha t^{2}$

As the initial angular velocity is zero. Hence we can calculate $\Theta$ the angle rotated in first 10 seconds by, $\Theta = \frac{1}{2}2^{2}\times 10 = 20 \: rad$

Number of revolutions, $\frac{\Theta }{2\pi} = \frac{20}{2\times 3.14} = 3.18$

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