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An element with electronic configuration of \mathrm{[Kr] 4d^{10} 5s^{0}} shall belong to

Option: 1

4th period, group 10
 


Option: 2

5th period, group 10
 


Option: 3

5th period, group 12


Option: 4

4th period, group 12


Answers (1)

best_answer

The element is Palladium (Pd). It is member of d-block (4d series i.e., 5th period) and It
has 10 electrons filled in after noble gas configuration which indicates it belongs to 10th
group.

Hence option 2 is correct.

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