An ideal gas is taken from state A (pressure P, volume V) to state B (pressure P/2, volume 2V) along a straight line in the P − V diagram as shown in fig. Then which is incorrect
The work done by the gas in the process A to B exceeds the work that would be done by it if the system were taken from A to B along the isotherm
In the T-V diagram, the path AB becomes a part of a parabola
In the P-T diagram, the path AB becomes a part of a hyperbola
In going from A to B, the temperature T of the gas first increases to a maximum and then decreases
(a) Work done in process A to B is (see fig.)
= area of trapezium ABCD
If the process A to B were isothermal, the work done would be
The equation of straight line AB is
....[1]
Which represents a parabola on the T-V graph
So choice (b) is also correct
......[2]
Which does not represent a hyperbola. So choice (c) is incorrect
(d) If follows from Eq. (2) above that choice (d) is correct