Benzaldehyde reacts with
a) ch3cho in the presence of dil NaOH
b) h2n-nh-benzene
c) conc NaOH
a) Benzaldehyde reacts with CH3CHO in the presence of dilute NaOH (Benzoin condensation)
$\text{C}_6\text{H}_5\text{CHO} + \text{CH}_3\text{CHO} \xrightarrow{\text{Dilute NaOH}} \text{C}_6\text{H}_5\text{CHOHCOH}$
b) Benzaldehyde reacts with H2N-NH-Benzene (Schiff base formation)
$\text{C}_6\text{H}_5\text{CHO} + \text{C}_6\text{H}_5\text{NH-NH}_2 \rightarrow \text{C}_6\text{H}_5\text{CH=NNH}\text{C}_6\text{H}_5$
c) Benzaldehyde reacts with concentrated NaOH (Aldol condensation)
$2 \, \text{C}_6\text{H}_5\text{CHO} \xrightarrow{\text{Conc. NaOH}} \text{C}_6\text{H}_5\text{CH=CHCHO}$