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Compressibility factor for \small N_2 at \small -50^{\circ}C and 800 atm pressure is 1.95. Calculate the number of moles of \small N_2 gas required to fill a gas cylinder of 100 L under the given conditions.

Option: 1

224.08


Option: 2

2240.8


Option: 3

3421.4


Option: 4

2435.2


Answers (1)

best_answer

We have given:
T=-50^{\circ}C or 223K
P = 800 atm
V = 100L
Z = 1.95


We know for compressibility factor:

Z=\frac{PV}{nRT}

n=\frac{800\times 100}{1.95 \times 0.082 \times 223}=2240.8

Therefore, Option(2) is correct.

Posted by

rishi.raj

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