Consider the following reaction:
The values of
,
and
in the reaction are, respectively:
5, 2 and 8
5, 2 and 16
2, 5 and 8
2, 5 and 16
The given reaction is:
Balancing the charges on both sides, we got
Balancing the O atoms on both sides, we got
Substituting the value of z in (1)
Now, substitute the value of y and z in terms of x in the original reaction:
Solving further we get,
by correlating, we get
x=2, y=5, z=16
Therefore,option(4) is correct