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Consider the following relations for emf of a electrochemical cell
(a) emf of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(b) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(c) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(d) emf of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)
Which of the above relations are correct?
(c) and (a)
(a) and (b)
(c) and (d)
(b) and (d)
Answers (1)
The EMF of a cell is given by the following expressions:
EMF = Reduction potential of cathode - Reduction potential of the anode
EMF = Reduction potential of cathode + Oxidation potential of the anode
EMF = Oxidation potential of anode - Oxidation potential of the cathode
Hence, the relations (b) and (d) are correct.
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