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  • Consider the reaction <img alt="\mathrm{M^{n+} + ne^- \rightarrow M(s)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BM%5E%7Bn&plus;%7D%20&plus;%20ne%5E-%20%5Cright

Consider the reaction \mathrm{M^{n+} + ne^- \rightarrow M(s)}. The standard reduction potential values of the elements M1, M2, and M3 are  -0.34 V , -3.05 V and -1.66 V respectively.The order of their reducing power will be

Option: 1

M_1>M_2> M_3


Option: 2

M_3>M_2> M_1


Option: 3

M_1>M_3> M_2


Option: 4

M_2>M_3> M_1


Answers (1)

best_answer

The more the negative reduction potential, the higher is the tendency to lose electrons.

Hence, the power of the reducing agent increases as the standard potential becomes more and more negative.

Thus, the correct order of reducing nature of the given metals is 

\mathrm{M_2>M_3>M_1}

Therefore, the correct answer is Option (4)

Posted by

himanshu.meshram

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