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During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is:

Option: 1

55 minutes


Option: 2

110 minutes


Option: 3

220 minutes


Option: 4

330 minutes


Answers (1)

We know the formula,

\mathrm{Q = I \times t}

where,

Q= quantity of electricity in coulomb

I = current in amperes = 3 A

t = time in seconds 

\mathrm{NaCl\rightarrow Na^++Cl^-}

\mathrm{2Cl^{-}\rightarrow Cl_2+2e^{-1}}

1 mole of electrons carries a charge = 96500 C.

\mathrm{96500\times 2 = 193000\ Coulomb} of electricity deposits 1 mole of \mathrm{Cl_2}

1 mole of \mathrm{Cl_2} is deposited by 193000 C

Thus 0.10 moles of  \mathrm{Cl_2} is deposited by

\mathrm{=\frac{193000}{1}\times 0.10=19300\ C}

\mathrm{19300\ C=3A\times t}

\mathrm{t=6433.3\ sec}

\mathrm{t = 107.22\ minutes}

\mathrm{t \approx 110 \ minutes}

Therefore, the correct option is (2)

Posted by

Sumit Saini

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