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  •  For a vertical circular motion having radius r as  shown in <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAJsAAACYCAYAAADz9ZsiAAAgAElEQVR4nOy9eZBl112gqYCOoCeamGFiOuimO5iBoOmgwR

 For a vertical circular motion having radius r as  shown in

 If u is the initial velocity imparted to body at point A then what is the velocity at point B  

Option: 1

\sqrt{u^{2}-2 gr}


Option: 2

\sqrt{u^{2}+ 2 gr}


Option: 3

\sqrt{u^{2} + gr}


Option: 4

\sqrt{u^{2}- gr}


Answers (1)

best_answer

As the velocity of the body at height h is given by

v = \sqrt{u^{2}-2 gr} = \sqrt{u^{2}-2 gr\left ( 1 - cos \theta \right )}

So put \theta = 90^{0}

We get v_{b} = \sqrt{u^{2}-2 gr}

Posted by

Kuldeep Maurya

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