-
Engineering and Architecture
Exams
Colleges
Predictors
Resources
-
Computer Application and IT
Quick Links
Colleges
-
Pharmacy
Colleges
Resources
-
Hospitality and Tourism
Colleges
Resources
Diploma Colleges
-
Competition
Other Exams
Resources
-
School
Exams
Top Schools
Products & Resources
-
Study Abroad
Top Countries
Student Visas
-
Arts, Commerce & Sciences
Exams
Colleges
Upcoming Events
Resources
-
Management and Business Administration
Colleges & Courses
Predictors
-
Learn
Online Courses
Engineering Preparation
Medical Preparation
-
Online Courses and Certifications
Top Streams
Specializations
- Digital Marketing Certification Courses
- Cyber Security Certification Courses
- Artificial Intelligence Certification Courses
- Business Analytics Certification Courses
- Data Science Certification Courses
- Cloud Computing Certification Courses
- Machine Learning Certification Courses
- View All Certification Courses
Resources
-
Medicine and Allied Sciences
Colleges
Predictors
Resources
-
Law
Resources
Colleges
-
Animation and Design
Predictors & Articles
Colleges
Resources
-
Media, Mass Communication and Journalism
Colleges
Resources
-
Finance & Accounts
Top Courses & Careers
Colleges
Get Answers to all your Questions
Q.72) Given below are two statements :
Statement 1 : Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at $273-278 \mathrm{~K}$. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult, and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below :
A) Statement I is incorrect but Statement II is correct
B) Both Statement I and Statement II are correct
C) Both Statement 1 and Statement II are incorrect
D) Statement I is correct but Statement II is incorrect
Answers (1)
Insertion of iodine into the benzene ring is indeed difficult. So iodobenzene is prepared via a Sandmeyer-type reaction from diazonium salt using KI.
Benzenediazonium salt is prepared at 273–278 K. This temperature range (0–5°C) is used to stabilize the diazonium ion during its formation, as higher temperatures can lead to its decomposition. It does not decompose easily in the dry state.
Hence, the correct answer is option (1).
NEET 2024 Most scoring concepts
- Just Study 32% of the NEET syllabus and Score up to 100% marks
