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  • Higher yield of NO in $\mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})$ can be obtained at [ $\Delta \mathrm{H}$ of the reaction $\left.=+180.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\right]$ A. higher temperature

Q.80) Higher yield of NO in $\mathrm{N}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})$ can be obtained at [ $\Delta \mathrm{H}$ of the reaction $\left.=+180.7 \mathrm{~kJ} \mathrm{~mol}^{-1}\right]$ A. higher temperature

B. lower temperature

C. higher concentration of $\mathrm{N}_2$

D. higher concentration of $\mathrm{O}_2$

Choose the correct answer from the options given below:-

A) A, C, D only

B) A, D only

C) B, C only

D) B, C, D only

 

Answers (1)

best_answer

Q.80) A. Higher temperature

According to Le Chatelier's Principle, increasing temperature favors the endothermic direction (forward reaction here), so more NO is formed.
B. Lower temperature

This would favor the exothermic direction (reverse reaction), forming less NO.
C. Higher concentration of $\mathbf{N}_{\mathbf{2}}$

Adding more reactant shifts equilibrium forward, increasing NO yield.
D. Higher concentration of $\mathrm{O}_{\mathbf{2}}$

Same logic as above - more reactants push the reaction forward.

Hence, the correct answer is option (1).

 

 

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