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In a guitar, two strings, A and B made of some material are slightly out of tune and produce beats of frequency 6Hz. When tension in B is slightly decreased, the beat frequency increases to7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:
Option: 1 523 Hz
Option: 2 524 Hz
Option: 3 536 Hz
Option: 4 537 Hz

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\\ Beat \ frequency \ = |f_A-f_B|=6$\\ \text{since tension in $B$ is decreased so it's frequency will also decrease} \\ \\ \text{New beat frequency =7 (increased by 1) So B must have smaller frequency} \\ Hence frequency of B $=f_A-6=530-6=524 Hz

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Deependra Verma

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