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Get Answers to all your Questions
In a hydrogen atom, if the energy of an electron in the ground state is then that in the 2nd excited state (in eV) is
Answers (1)
In hydrogen atom, $E_n = \dfrac{-13.6}{n^2},\text{eV}$
For ground state, $n = 1$
So, for the second excited state, $n = 3$
Energy in second excited state $E_3 = \dfrac{-13.6}{3^2} = \dfrac{-13.6}{9} = -1.51,\text{eV}$.
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