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  • In the expression of percentage oxygen calculation <img alt="\mathrm{\%O=\frac{32 * m_{1} * 100}{88 * m}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%5C%25O%3D%5Cfrac%7B32%20

In the expression of percentage oxygen calculation \mathrm{\%O=\frac{32 * m_{1} * 100}{88 * m}} , \mathrm{m_{1}, m}   respectively are

Option: 1

mass of organic compound and mass of CO_2


Option: 2

mass of \mathrm{BaSO_4} and mass of organic compound


Option: 3

mass of organic compound and mass of \mathrm{BaSO_4}


Option: 4

mass of \mathrm{CO_2}  and mass of organic compound


Answers (1)

best_answer

As we have learnt,

A definite mass of an organic compound is decomposed by heating in a stream of nitrogen gas. The mixture of gaseous products containing oxygen is passed over red-hot coke when all the oxygen is converted to carbon monoxide. This mixture is passed through warm iodine pentoxide (I2O5) when carbon monoxide is oxidised to carbon dioxide producing iodine.

Thus, \mathrm{88 \ g\ of\ CO_2} is obtained from \mathrm{32 \ g\ of\ O_2}

Let the mass of organic compound taken be \mathrm{m\ g}
Mass of carbon dioxide produced be \mathrm{m_1\ g}

\mathrm{\therefore m_1 \ g } carbon dioxide is obtained from \mathrm{\frac{32 \times m_{1}}{88} \mathrm{g}\: \mathrm{O}_{2}}

Therefore, the % of Oxygen in Organic compound is given as 

\mathrm{\% \ Oxygen=\frac{32\times m_{1}\times 100}{88\times m}}

So, from the above, it is evident that 

\mathrm{m_{1}=Mass\:of\:Carbon\ dioxide}

\mathrm{m=Mass\:of\:organic\ compound}

Hence, the correct answer is Option (4)

Posted by

Anam Khan

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