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  • In YDSE,  is the fringe width M and N are the two slits. The central maximum is formed at a point O. After some

In YDSE, \beta is the fringe width M and N are the two slits. The central maximum is formed at a point O. After some time, the central maximum is found to be shifted by t(\mu-1)$ $\frac{\beta}{\lambda} towards A. Which of the followings is correct ?

Option: 1

 A thin film of thickness t is placed in front of B


Option: 2

A thin film of refractive index \mu is placed in behind B


Option: 3

A thin film of thickness t and refractive index \mu is placed in front of A


Option: 4

 A thin film of thickness t and refractive index \mu is placed behind A


Answers (1)

best_answer

Path difference due to film =\mathrm{t}(\mu-1)
Path difference at a point \mathrm{x} from the centre of screen \mathrm{=x \frac{d}{D}}

\mathrm{\therefore \mathrm{t}(\mu-1)=\mathrm{x} \frac{\mathrm{d}}{\mathrm{D}} \Rightarrow \mathrm{x}=\mathrm{t}(\mu-1) \frac{\mathrm{D}}{\mathrm{d}} }
\mathrm{\because \beta=\frac{\lambda \mathrm{D}}{\mathrm{d}} \therefore \frac{\mathrm{D}}{\mathrm{d}}=\frac{\mathrm{B}}{\lambda }
\mathrm{\therefore \mathrm{x}=\mathrm{t}(\mu-1) \frac{\beta}{\lambda} }.

Posted by

rishi.raj

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