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n_1 is the frequency of the pipe closed at one end and n_2 is the frequency of the pipe open at both ends. If both are joined end to end, find the fundamental frequency of closed pipe, so formed 

Option: 1

\frac{n_1n_2}{n_2+2n_1}


Option: 2

\frac{n_1n_2}{2n_2+n_1}


Option: 3

\frac{2n_1+n_2}{n_2n_1}


Option: 4

\frac{2n_1+n_2}{n_2n_1}


Answers (1)

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Frequency of closed pipe, n_1 = \frac{v}{2l_1}\Rightarrow l_1 =\frac{v}{4n_1}

Frequency of open pipe, n_2 = \frac{v}{2l_2}\Rightarrow l_2 =\frac{v}{2n_2}

When both pipes are joined, then length of closed pipe

l=l_1+l_2

\frac{v}{4n}=\frac{v}{4n_1}+\frac{v}{2n_2}

\frac{v}{2n}=\frac{v}{2n_1}+\frac{v}{n_2}

\frac{1}{2n}=\frac{1}{2n_1}+\frac{1}{n_2}

\frac{1}{2n}=\frac{n_2+2n_1}{2n_1n_2}

n=\frac{n_1n_2}{n_2+2n_1}

Posted by

Divya Prakash Singh

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