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A beam of light \lambda =600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is:

  • Option 1)

    1.2 cm

  • Option 2)

    1.2 mm

  • Option 3)

    2.4 cm

  • Option 4)

    2.4 mm

 

Answers (1)

As we learnt in

Fraunhofer Diffraction -

bsin heta = nlambda
 

- wherein

Condition of nth minima.

b= slit width

heta = angle of deviation

 

 distance between first daic fringe on both side means width of central maxima 

\therefore\Delta y = \frac{2\lambda D}{b}=\frac{2\times600\times10^{-9}\times2m}{10^{-3}m}

\Deltay=2.4mm


Option 1)

1.2 cm

This is incorrect option 

Option 2)

1.2 mm

This is incorrect option 

Option 3)

2.4 cm

This is incorrect option 

Option 4)

2.4 mm

This is correct option 

Posted by

Vakul

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