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Potassium does not show an oxidation state of +2 due to its- 

 

Option: 1

High first ionization potential

 


Option: 2

High second ionization potential

 


Option: 3

Small ionic radius

 


Option: 4

None of the above


Answers (1)

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The electronic configuration of K is  [\mathrm{Ar}] 4 \mathrm{s}^1=1 \mathrm{s}^2, 2 \mathrm{s}^2, 2 \mathrm{p}^6, 3 \mathrm{s}^2, 3 \mathrm{p}^6, 4 \mathrm{s}^1 . .

To complete the octet, \mathrm{K} loses one electron and attains the stable electronic configuration of 2, 8, 8. \mathrm{K} after loosing one electron become \mathrm{K}^{+}.

The electronic configuration of \mathrm{K}^{+} 2,8 which is more stable than that of \mathrm{K}. It does not tend to loose one more electron and become unstable. Due to this, its second ionization energy is very high.

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mansi

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