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The critical temperature of \small O_2 is less than \small H_2O because the \small H_2O molecules have:

Option: 1

Two covalent bonds


Option: 2

Dipole moment


Option: 3

Fewer electrons than O_2


Option: 4

V-shaped structure


Answers (1)

best_answer

We know that the dipole moment in a molecule results in strong intermolecular forces and since

T_c=\frac{8a}{27Rb}
Thus, the critical temperature of H_2O is more for O_2 .
Therefore, Option(2) is correct

Posted by

Ritika Kankaria

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