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  • The following solutions were prepared by dissolving 10 g of glucose <img alt="\mathrm{(C_{6}H_{12}O_{6})}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%28C_%7B6%7DH_%7B12%7DO_%

The following solutions were prepared by dissolving 10 g of glucose \mathrm{(C_{6}H_{12}O_{6})} in 250 ml of water \mathrm{(P_{1}),} 10 g of urea \mathrm{(CH_{4}N_{2}O)} in 250 ml of water \mathrm{(P_{2}),} and 10 g of sucrose \mathrm{(C_{12}H_{22}O_{11})} in 250 ml of water \mathrm{(P_{3})}. The right option for the decreasing order of osmotic pressure of these solutions is :

Option: 1

\mathrm{P_{2}>P_{1}>P_{3}}


Option: 2

\mathrm{P_{1}>P_{2}>P_{3}}


Option: 3

\mathrm{P_{2}>P_{3}>P_{1}}

 


Option: 4

\mathrm{P_{3}>P_{1}>P_{2}}


Answers (1)

best_answer

We know that,

\mathrm{\pi = CRT}

So under similar conditions of temperature and volume of solution, the species with the greater number of moles has a greater value of Osmotic Pressure.

Order of moles : Urea > Glucose > Sucrose

Order of Osmotic Pressure: 

\mathrm{P_{2}>P_{1}>P_{3}}

Option 1 is correct.

Posted by

Divya Prakash Singh

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