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The freezing point depression constant \mathrm{(K_{f})} of benzene is \mathrm{5.12\ K\ kg\ mol^{-1}}. The freezing point of depression for the solution of molality 0.078 m containing a non- electrolyte solute in benzene is (rounded off upto two decimal places):

Option: 1

0.60K


Option: 2

0.20K


Option: 3

0.80K

 


Option: 4

0.40K


Answers (1)

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The formula for depression in freezing point is (for non-electrolyte solute) - 

\mathrm{\Delta T_f = K_f \times m}

\mathrm{\Delta T_f = 5.12 \times 0.078 = 0.399\ K}

\mathrm{\Delta T_f \approx 0.40 \ K}

Therefore, the correct option is (4).

Posted by

Ajit Kumar Dubey

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