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Get Answers to all your Questions
Q.44) The, Kinetic energies of two similar cars A and B ard 100 J and 225 J respectively. On applying breaks, car A stops after 1000 m and car $B$ stops after 1500 m . If $F_A$ and $F_B$ are the forues applied by the breaks on cars A and B , respectively, then the ratio $F_A / F_D$ is
A) $-\frac{1}{2}$
B) $\frac{3}{2}$
C) $\frac{2}{3}$
D) $\frac{1}{3}$
Answers (1)
Given: Car A: $K_A = 100,J$, $d_A = 1000,m$ Car B: $K_B = 225,J$, $d_B = 1500,m$
Using work-energy theorem: $F = -\frac{K}{d}$ So, $F_A = -\frac{100}{1000} = -0.1,N$, $F_B = -\frac{225}{1500} = -0.15,N$
Now, $\frac{F_A}{F_B} = \frac{-0.1}{-0.15} = \frac{2}{3}$
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