Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The pressure exerted by 5 moles of    in one litre vessel at  

The pressure exerted by 5 moles of  \small CO_2  in one litre vessel at  \small 47^{\circ}C  using Van der Waals equation is x atm while the pressure is y atm if it behaves ideally in nature. The value of x and y respectively are
(Given, \small a=3.592atm\: L^2\: mol^{-2} , \small b=0.0427Lmol^{-1} )

Option: 1

67.43 atm, 131.36 atm
 


Option: 2

77.21 atm, 134 atm


Option: 3

131.36 atm, 77.21 atm


Option: 4

77.21 atm, 131.36 atm


Answers (1)

best_answer

We have:
V = 1 litre
T = 320K
a = 3.592
b = 0.0427
n = 5
Now, According to Van der Waals equation, we have:

\left ( P+\frac{an^2}{V^2} \right )(V-nb)=nRT

\left ( P+\frac{(5)^2\times 3.592}{(1)^2} \right )(1-5\times 0.0427)=5\times 0.0821 \times 320

\Rightarrow \mathrm{ P = 77.218\ atm }

Thus, the pressure is 77.218 atm when the gas shows real gas behaviour.

Now, if the gas behaves like ideal gas, then, we know:

\mathrm{PV = nRT}
\Rightarrow \mathrm{P \times 1 = 5 \times 0.0821 \times 320}
\Rightarrow \mathrm{P = 131.36 \ atm}

Thus, the pressure is 131.36 atm when the gas behaves ideally.
Therefore, Option(4) is correct

Posted by

Deependra Verma

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

17 left in NEET toppers list 2024 as physics question strips 44 of top ranks
anam-khan

NEET Revised Result 2024: Joy and disappointment as all-India ranks change by thousands of places
anam-khan

NEET UG 2024 cut-offs drop for all categories; final scorecard out at neet.ntaonline.in

Latest Question